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(H)=-16H^2+152H+80
We move all terms to the left:
(H)-(-16H^2+152H+80)=0
We get rid of parentheses
16H^2-152H+H-80=0
We add all the numbers together, and all the variables
16H^2-151H-80=0
a = 16; b = -151; c = -80;
Δ = b2-4ac
Δ = -1512-4·16·(-80)
Δ = 27921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-151)-\sqrt{27921}}{2*16}=\frac{151-\sqrt{27921}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-151)+\sqrt{27921}}{2*16}=\frac{151+\sqrt{27921}}{32} $
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